Enter Modular Exponentiation
Solve 36 mod 17 using:
Modular exponentiation
Build an algorithm:
n is our exponent = 6
y = 1 and u ≡ 3 mod 17 = 3
See here
n = 6 is even
Since 6 is even, we keep y = 1
Determine u2 mod p
u2 mod p = 32 mod 17
u2 mod p = 9 mod 17
9 mod 17 = 9Reset u to this value
Cut n in half and take the integer
6 ÷ 2 = 3
n = 3 is odd
Since 3 is odd, calculate (y)(u) mod p
(y)(u) mod p = (1)(9) mod 17
(y)(u) mod p = 9 mod 17
9 mod 17 = 9Reset y to this value
Determine u2 mod p
u2 mod p = 92 mod 17
u2 mod p = 81 mod 17
81 mod 17 = 13Reset u to this value
Cut n in half and take the integer
3 ÷ 2 = 1
n = 1 is odd
Since 1 is odd, calculate (y)(u) mod p
(y)(u) mod p = (9)(13) mod 17
(y)(u) mod p = 117 mod 17
117 mod 17 = 15Reset y to this value
Determine u2 mod p
u2 mod p = 132 mod 17
u2 mod p = 169 mod 17
169 mod 17 = 16Reset u to this value
Cut n in half and take the integer
1 ÷ 2 = 0
Because n = 0, we stop
We have our answer
Final Answer
36 mod 17 ≡ 15
You have 1 free calculations remaining
What is the Answer?
36 mod 17 ≡ 15
How does the Modular Exponentiation and Successive Squaring Calculator work?
Free Modular Exponentiation and Successive Squaring Calculator - Solves xn mod p using the following methods: * Modular Exponentiation * Successive SquaringThis calculator has 1 input.
What 1 formula is used for the Modular Exponentiation and Successive Squaring Calculator?
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What 6 concepts are covered in the Modular Exponentiation and Successive Squaring Calculator?
- exponent
- The power to raise a number
- integer
- a whole number; a number that is not a fraction...,-5,-4,-3,-2,-1,0,1,2,3,4,5,...
- modular exponentiation
- the remainder when an integer b (the base) is raised to the power e (the exponent), and divided by a positive integer m (the modulus)
- modulus
- the remainder of a division, after one number is divided by another.a mod b
- remainder
- The portion of a division operation leftover after dividing two integers
- successive squaring
- an algorithm to compute in a finite field
